calculus - Show that the pedal equation of the curve $x=a(2\cos t-\cos2t),\ y=a(2\sin t-\sin2t)$ is $9(r^2-a^2 )=8p^2$ - Mathematics Stack Exchange
![The pedal equation of the circle ${{x}^{2}}+{{y}^{2}}=4$ with regard to the point (2,0) is[a] ${{r}^{2}}=4$[b] $4p={{r}^{2}}$[c] ${{p}^{2}}=4r$[d] $p=4{{r}^{2}}$](https://www.vedantu.com/question-sets/e2a07293-3d27-46db-ac64-b66e9ca8db868341228550344539173.png "The pedal equation of the circle ${{x}^{2}}+{{y}^{2}}=4$ with regard to the point (2,0) is[a] ${{r}^{2}}=4$[b] $4p={{r}^{2}}$[c] ${{p}^{2}}=4r$[d] $p=4{{r}^{2}}$")
The pedal equation of the circle ${{x}^{2}}+{{y}^{2}}=4$ with regard to the point (2,0) is[a] ${{r}^{2}}=4$[b] $4p={{r}^{2}}$[c] ${{p}^{2}}=4r$[d] $p=4{{r}^{2}}$
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